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Inclined planes with applied force and connected masses

G2.3 G2.4

By the end of this lesson you should be able to

  • Describe the forces acting on an object on an inclined plane through the use of free-body diagrams. G2.3
  • Determine the net force acting on an object on an inclined plane using vector analysis. G2.4

Key ideas

  • Choose a positive direction along the slope (usually the direction of motion) and add forces with signs.
  • An applied force along the slope needs no resolving.
  • Friction always opposes the motion (or the tendency to move).
  • For connected masses on a light string over a frictionless pulley, the tension is the same at both ends and both masses share the same acceleration.

Key formulas (QCAA formula book notation)

\[ F_{net} = F_A - m g\sin\theta - F_f = m a \quad \text{(pushed up the slope)} \]
Worked example

A 900 kg car accelerates up a 10° hill at 0.50 m s⁻² against 600 N of friction. Find the driving force.

  1. \(m g\sin\theta = 900 \times 9.8 \times \sin 10^\circ = 1532\) N
  2. \(F_A = ma + mg\sin\theta + F_f = 450 + 1532 + 600 = 2.6 \times 10^3\) N

Common mistakes

  • Forgetting the weight component when moving up a slope.
  • Giving each connected mass a different acceleration.

Do

  • Read: Textbook (Oxford Physics for Queensland Units 3 & 4) section 3.3
  • Do: CYL 3.3 Q6, 7; CYL 3.2 Q11

Try it

Watch

Further reading


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