Electrical Circuits
Syllabus reference
Unit 1, Topic 3 — 15 hours (including practicals)
Electric current
Electric charge is a fundamental property of matter. The SI unit is the coulomb (C). The charge on a single electron is \(e = -1.6 \times 10^{-19}\) C.
Conventional current flows from positive to negative (the direction a positive charge would move). Electron flow is in the opposite direction.
Key formula
where \(I\) = current (A), \(q\) = charge (C), \(t\) = time (s)
Potential difference
Electrical potential difference (voltage) is the work done per unit charge as charge moves between two points in a circuit. EMF (electromotive force) is the potential difference across the terminals of a source when no current flows.
Key formula
where \(V\) = potential difference (V), \(W\) = work done (J), \(q\) = charge (C)
Resistance
Resistance is a measure of how much a component opposes the flow of current. An ohmic resistor has a constant resistance (linear V–I graph). A non-ohmic resistor has a resistance that changes with current or voltage.
Ohm's law
where \(V\) = potential difference (V), \(I\) = current (A), \(R\) = resistance (Ω)
Mandatory practical: Ohmic and non-ohmic resistors
Compare the characteristics of ohmic and non-ohmic resistors experimentally. Interpret graphical representations of V vs I data to find resistance using the gradient and its uncertainty.
Power
Key formulas
where \(P\) = power (W)
Series and parallel
Series circuits
Components connected end-to-end. Current is the same through each component; voltage is shared.
[ R_t = R_1 + R_2 + \cdots + R_n ] [ V_t = V_1 + V_2 + \cdots + V_n ] [ I_t = I_1 = I_2 = \cdots = I_n ]
Parallel circuits
Components connected across the same two points. Voltage is the same across each branch; current is shared.
[ \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n} ] [ V_t = V_1 = V_2 = \cdots = V_n ] [ I_t = I_1 + I_2 + \cdots + I_n ]
Circuit analysis
Worked example: Series–parallel circuit
Question: A circuit has a 12 V battery connected to a 4 Ω resistor in series with two parallel resistors of 6 Ω and 3 Ω. Find the total current.
Solution:
Parallel combination: \(\frac{1}{R_p} = \frac{1}{6} + \frac{1}{3} = \frac{1}{2}\), so \(R_p = 2 \text{ Ω}\)
Total resistance: \(R_t = 4 + 2 = 6 \text{ Ω}\)
Total current: \(I = \frac{V}{R_t} = \frac{12}{6} = 2.0 \text{ A}\)
Power dissipation over resistors in a circuit is calculated using \(P = I^2R\) or \(P = \frac{V^2}{R}\) for each component.
Standard circuit symbols
Construct electrical circuit diagrams using standard symbols for: resistor, voltmeter, ammeter, cell, battery, switch, lamp.
Simulations and videos
PhET Simulations:
- Circuit Construction Kit: DC — build and analyse circuits
Crash Course Physics:
- Electric Current (Physics #28)
- Voltage, Electric Energy, and Capacitors (Physics #27)
- DC Resistors and Batteries (Physics #29)
- Circuit Analysis (Physics #30)
External resources: